You are given a parallel-plate capacitor with square plates ofarea A, and separation d, in a vacuum. Each plate has a charge q.There is no battery nor any other source of charge connected to theplates. If the plate area is doubled, explain what happensto: a) The surface charge density (The exercise goes further and the surface charge density isthe only part I dont actually understand) You are given a parallel-plate capacitor with square plates ofarea A, and separation d, in a vacuum. Each plate has a charge q.There is no battery nor any other source of charge connected to theplates. If the plate area is doubled, explain what happensto: a) The surface charge density (The exercise goes further and the surface charge density isthe only part I dont actually understand)
Explanation / Answer
= q / A if area of the plates are doubled A = 2A then the surface charge densitydecreases to half of its value