A soccer player horizontally kicks a ball of mass 0.608 Kg which isinitially at

Question

A soccer player horizontally kicks a ball of mass 0.608 Kg which isinitially at rest. The player's foot is in contact with the ballfor 253.1 miliseconds. If the ball reaches a speed of 3.69 m/s inthis time determine:
A) the impulse delivered to the ball B) the average force imparted to the ball; and C) the acceleration of the ball as it was kicked.
Kindly provide explanations of each steps..
A) the impulse delivered to the ball B) the average force imparted to the ball; and C) the acceleration of the ball as it was kicked.
Kindly provide explanations of each steps..

Explanation / Answer

   mass, m = 0.608 kg    initial velocity, U = 0    final velocity, V = 3.69 m/s    time of contact, t = 253.1 ms = 0.2531s A)    impulse, I = Change in momentum = m ( V - U)                                                        = 0.608 * 3.69 = 2.244 kg m/ s = 2.244 Ns B)    Impulse , I = Force * time          2.244 =F * 0.2531    Force, F= 8.87 N C)    acceleration, a = F / m = 8.87 / 0.608= 14.58m/s^2

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