A tennis player receives a shot with the ball (0.0600 kg) travelinghorizontally

Question

A tennis player receives a shot with the ball (0.0600 kg) travelinghorizontally at 54.0 m/s and returns theshot with the ball traveling horizontally at 38.0 m/s in the opposite direction. (Assume theinitial direction of the ball is in the -x direction.) (a) What is the impulse delivered to the ballby the racket?
1 N·s2Direction+x-x

(b) What work does the racket do on the ball?
3 J (a) What is the impulse delivered to the ballby the racket?
1 N·s2Direction+x-x

(b) What work does the racket do on the ball?
3 J

Explanation / Answer

.      Mass (m) = 0.0600 kg .      Initial velocity ( v1 ) = 54.0 m/s .      Final velocity (v2) = - 38.0 m /s ( since it is inopposite direction ) . (a) Impulse is : .       J = m ( v2 - v1 ) = 0.0600 ( - 38.0 - 54.0 ) = - 5.52 N-s In " - x " direction. . (b) Work does on the ball is : .       W = change in K.E .       = 1/2 m(v2)2   - 1 /2 m (v1)2   .       = 0.5 * 0.0600 [(-38.0)2   - (54.0)2  ] .       = ---------- J . Solve the above. . Hope this hleps u!

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