Part A Find the equivalent resistance of R1 and R2. Part B Find the resistance f

Question

Part A

Find the equivalent resistance of R1 and R2.

Part B

Find the resistance from A to C.

Part C

Find the total resistance of the circuit.

Part D

Find the current passing through the battery ( Total Current)

Part E

Find the current in I4, passing through R4.

Part F

Find the current I1 through R1.

Part G

The voltage drop across a resistor is the current going through that resistor multiplied by the resistance of the resistor.

Find the voltage drop across R5

Part H

Find the voltage drop across R3.

Explanation / Answer

Part A :Find the equivalent resistance of R1 and R2

Since R1 and R2 are in parallel
Equivalent Resistance (R') is
(1/R') = (1/R1) + (1/R2) = .(1/80) + (1/80) = 2/80
R' = 40 ohms

Part B

The resistance from A to C : R'
Resistance from A to C is equal to R5=10 ohms (Wrong according to you)

Part C

The total resistance of the circuit: R'
Resistnace from C to A
1/R'' = 1/(40+30)+(1/70) = 2/70
R'' = 35 ohms

Total resistance R' = R'' + R5 = 45 ohms

Part D

The current passing through the battery ( Total Current)
I = V/R = 140/45 = 3.1 A

Part E

The current, I4, passing through R4.
Voltage drop between C and A = 140 - Volatge drop at R5 = 140 - I.R5 = 140- 3.1x10 = 109V
Current flowing throw R4: I4 = 3.1 - Current flowing through R3 = 3.1 - (109/70) = 1.54 A

Part F

The current I1 through R1.
Voltage about R1 = 1.54 x 40 = 61.7 V
Current through R1 is:
I1 = 61.7/80 = 0.77 A

Part G

Find the voltage drop across R5 = I.(R5) = 3.1 x 10 =31V

Part H

Find the voltage drop across R3. = 140 - voltage drop across R5 = 140 -31 = 109 V

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