Two bicycle tires are set rolling with the same initial speed of 3.90m/s along a

Question

Two bicycle tires are set rolling with the same initial speed of 3.90m/s along a long, straight road, and the distance each travels before its speed is reduced by half is measured. One tire is inflated to a pressure of 40 psi and goes a distance of 17.1m ; the other is at 105 psi and goes a distance of 92.4m . Assume that the net horizontal force is due to rolling friction only and take the free-fall acceleration to be g = 9.80m/s2 .

What is the coefficient of rolling friction ?r for the tire under low pressure?

Part B is not shown yet.

Explanation / Answer

Initla speed of bicycles

Vi=3.9 m/s

Final speed of bicyles

Vf=3.9/2 =1.95 m/s

The coefficent of rolling friction is given by

uk=(Vi2-Vf2)/2gf =(3.92-1.952)/2*9.8*17.1

uk=0.034

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