Question
Need help solving step by step
of radius 0.90 m. Caleulate tio 4. (II) What is the magnitude of the acceleration of a speck of clay on the edge of a potter's wheel turning at 45 rpm (revolutions per minute) if the wheel's diameter is 35 cm? 5. (II) A 0.55-kg ball, attached to the end of a horizontal cord, is revolved in a circle of radius 1.3 m on a frictionless horizontal surface. If the cord will break when the tension in it exceeds 75 N, what is the maximum speed the ball can have? st centrifuge rotate if a particle
Explanation / Answer
a) a ( acceleration) =v^2/ r = ( w^2 r^2/r) = w^2 r
w= 45 prm = 4.712 rad/sec
a = 4.712^2 ( 0.175) =3.88 m/S^2
b) T = mv^2/ r
75 = (0.55) v^2/1.3
v = 13.314 m/s apprx