Here we learn how to apply the concept of the ideal-gas law in an isobaric proce

Question

Here we learn how to apply the concept of the ideal-gas law in an isobaric process to calculate the final gas temperature Problem 12.27 - Enhanced with Feedback A gas with an initial temperature of 560 °C undergoes the process shown in (Figure 1). Significant Figures Feedback: Your answer 4.6 C was either rounded differently or used a different number of significant figures than required for this part. You may want to review (pages 367 -372) Part C How many moles of gas are there? Express your answer using two significant figures Figure 1 4 of 1 A2op p (atm) mol Submit My Answers Give Up Incorrect; Try Again; 3 attempts remaining You have substituted values of the temperature and the volume corresponding to different points on the pV diagram Recall that the ideal-gas law should be applied to a certain point of the process 0 V (cm) 0 100 200 300

Explanation / Answer

we can solve for n,

n = p*V/RT

use either condition to get

n = 3*1.013*10^5*300/10^6/(8.314*(550+273))

=1.32*10^-2 mol

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