If you were to lower the small glass tube into the water in the larger cylinder,

Question

If you were to lower the small glass tube into the water in the larger cylinder, how would you expect the pressure of the air in the small glass tube to change? Write down a formula expressing the pressure measured by the sensor (connected to the glass tube) in terms of the depth, i.e. the distance from the water surface to the water level in the tube

Assume that the density of water is , the depth of liquid in the tube is h, the cross sectional area of the tube is A, and the acceleration due to gravity is g. Write the SYMBOLLIC formula using the symbols provided here

Explanation / Answer

As the depth increases the pressure also increases.

Pressure at a depth h,

P = Po + rho*g*h

here, Po = atmosperic pressure( 1 atm or 1.013*10^5 pa)

rho = density of water(1000 kg/m^3)

g = acceleration due to gravity (9.8 m/s^2)

h = the depth (in m)

Note : The pressure does not depend on cross sectional area of the tube.

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