Quantitative Prelecture Video: Rotational Motion Max is pushing on the edge (2.4

Question

Quantitative Prelecture Video: Rotational Motion Max is pushing on the edge (2.4 m from the center) of the merry-go-round to make it rotate. Maya is riding on the merry-go-round, sitting 1.2 m from the center. If Max is pushing the merry-go-round at 1.4 m/s, how fast is Maya moving? Click Play to watch the video below. Answer the ungraded questions in the video and the graded follow-up questions at right O 1.4 m/s O 0.58 m/s 4.0 m/s O 2.1 m/s O 0.70 m/s The pepper is 0.25 m from the center of the turntable, and the salt is 0.20 m from the center m] Submit My Answers Give UD : (O 25-n)(1.3 rad): O 33 m Part C Max is pushing on the edge (2.4 m from the center) of the merry-go-round to make it rotate. Maya is riding on the merry-go-round, sitting 1.2 m from the center. If Max increases the merry-go-round's angular speed from 0.52 rev/s to 1.5 rev/s in 2.2 s, what is the merry-go-round's angular acceleration? O 2.8 rad/s2 0.45 rad/s O 5.8 rad/s2 O 3.4 rad/s2 6.7 rad/s2

Explanation / Answer

Part B:

Rotational velocity of each point will be constant.

Means -

w = v1/r1 = v2/r2

=> 1.4/2.4 = v2 / 1.2

=> v2 = (1.4*1.2) / 2.4 = 0.7 m/s

Hence last option is the correct answer.

Part C:

Max increases the angular acceleration of the merry-go-round ,

alpha = (1.5 - 0.52) / 2.2 = 0.445 rev / s^2 = (0.445*2*pi) rad/s^2 = 2.80 rad/s^2

So, first option is the correct answer.

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