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Part A Exercise 26.39 For a wire carrying this maximum current, find the magneti

ID: 1784484 • Letter: P

Question

Part A Exercise 26.39 For a wire carrying this maximum current, find the magnetic field strength 0.120 mm from the wire's axis. Number 12 wiring, is 2.053 mm in diameter and can safely carry currents of up to 20.0 A gauge wire, commonly used in household Submit My Answers Give Up Part B For a wire carrying this maximum current, find the magnetic field strength at the wire's surface B-3.90x103 T Submit My Answers Give Up Correct Significant Figures Feedback: Your answer 38.96.10 4 = 3.896x 10-3 T was either rounded differently or used a different number of significant figures than required for this part. Part C For a wire carrying this maximum current, find the magnetic field strength 0.395 mm beyond the wire's surface.

Explanation / Answer

a)

Magnetic field inside the wire is given by

B=uoIr/2piR2 =(4pi*10-7)*20*(0.12*10-3)/2pi*(2.053*10-3/2)2

B=4.56*10-4 T

b)

Magnetic field on the surface is

B=uoI/2piR=(4pi*10-7)*20)/2pi*(2.053*10-3/2)

B=3.9*10-3 T

c)

Magnetic field outside the wire is given by

B=uoI/2pir

Here r=(2.053/2)+0.395=1.4215 mm

B=(4pi*10-7)*20)/2pi*(1.4215*10-3)=2.81*10-3T