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There are two circuits drawn below. They are the same except for the central res

ID: 1785908 • Letter: T

Question

There are two circuits drawn below. They are the same except for the central resistor. All the resistor values are the same, 50.

The left hand circuit is only presented to help you think about these questions.

(1) In these circuits or any others, current flows through a given resistor for one reason and one reason only. What is it?

a. There is a 1.5 Volt battery present.

b. There is a voltage change from one end of the resistor to the other.

c. There is a DVM present.

d. There is a complete circuit somewhere in the diagram.

Keeping in mind the question asked just above, Describe the current that flows in the center resistor of the right hand circuit. As a hint, you can compute the answer but you do not need to.

(2) What is the size of the current? 0.10A, More than 0.10A, 0.05 A, or Zero - there is no current.

(3) Which direction does the current flow? From right to left, Neither direction as there is no current, or From left to right.

5 Volts 5 Volts 50 Ohms 50 Ohms 50 Ohms 50 Ohms 50 Ohms 50 Ohms o Ohms 50 Ohms 50 Ohms 0 Volts 0 Volts

Explanation / Answer

(a) here given that all the resistor are 50 ohms in both circuit at one point the voltage is 5 volt and other point the voltage is zero volt .

as we know that the current flow from high voltage to low voltage due to generate electric field between them

so in both circuit there will be current flow from 5 volt to 0 volt               Ans

(b) in figure one there is a series combination so

                50 + 50 = 100 ohm             and        50 + 50 = 100 ohm

now both are in parallel so total resistance

                            R = (100 x 100 ) / (100 + 100)

                           R = 50 ohm

so the current     Ia = 5 / 50 = 0.1 Amp                   Ans

in circuit b there is two series combination

     50 + 50 = 100 ohm            and           50 + 50 = 100 ohm

now 100 ohm and 50 ohm and 100 ohm are in parallel

so the total resistance      

                  1 / R = (1/100) + (1/50) + (1/100)

                          = 0.01 + 0.02 + 0.01

                      R = 1 /0.04 = 25 ohm                

so the current           Ib = 5 / 25 = 0.2 Amp             Ans

(c) from the equilent circuit we can say that the current will flow from left to right because left side voltage is much large than right side voltage