Description Chapter 9 homework gnment Submssl For this assignment, you submit an
ID: 1787120 • Letter: D
Question
Description Chapter 9 homework gnment Submssl For this assignment, you submit answers by question parts. The number of submissions remaining for each queetion part onychangesi you subrit or change the answer Instructions You have 5 allowed submissions Assignment Scoring Your last subnmission is used for your soore. Four acrobats of mass 74.0 kg, 68.0 kg, 62.0 kg, and 55.0 kg form a hu man tower with each acrobat standing on the shoulders of another acrobat. The 74 74.0-kg acrobat is at the bottom of the tower (a) What is the normal force acting on the 74.0-kg acrobat? area of each of the 74.0-kg acrobat's shoes is 497 cm2, what average pressure (not including atmospheric pressure) does the column of acrobats exert on the floor? Pa (c) Will the pressure be the same if a different acrobat is on the bottom? This answer has not been graded yet Need Help? Raxd N Taik to a Tuter My Notes Ask Your 2.-/3 points SercPe 9.P.024 The deepest point in the ocean is in the Mariana Trench, about 11 km deep. The pressure at that point is huge, about 1.13 x 108 N/m2 late the chanes in volume of 1.00 m3 of water carried from the surface to the bottom of the Pacific.Explanation / Answer
a] Lets take all the four acrobat as a system, So normal at bottom has to balance combined weight.
N = (m1+m2+m3+m4)g = (74+68+62+55)*9.8 = 2538.2 N answer
b] Pressure = Normal/area = 2538.2/[2*497e-4] = 25535 Pa
c] If area of shoes is same, then pressure will be same. If we assume area to be same, then Yes pressure will be same, otherwise it will not be same.