Please Help show work PLEASE Proiectile Motion: Be able to make graphs of the mo
ID: 1789231 • Letter: P
Question
Please Help show work PLEASE
Proiectile Motion: Be able to make graphs of the motion of a projectile, including horizontal and vertical position and velocity graphs. The origin of the axes may be located at the beginning or end of the motion. Given graphs of position versus time and/or velocity versus time for a projectile and the fit equations for each, be able to determine the initial position(s)/velocities and accelerations throughout the motion. SAMPLE Two graphs of horizontal position-versus-time and vertical velocity-versus-time for a ball in projectile motion on an alien planet are shown below. Also given is the "Fit Equation" for these lines Note: The values given are in SI units: distance is in meters, and time in seconds ball (t, x) ball (t, Vy) 0.6 0.5 0.4 -0.5 0.2 2.0 0.2 0.6 0.8 0.2 0.3 0.4 0.5 0.6 0.7 0.8 Fit Equation Fit Equation x = (0.66)t + (-0.09) uy = (-3.826)t + 1.412 ·What is the initial speed of the ball, ie, how fast is the ball moving? . At what angle from the horizontal is the ball initially moving? » What is the vertical acceleration of the ball? Include units. What is the horizontal acceleration of the ball? Include units [Remember: The ball is not on Earth.]Explanation / Answer
x = 0.66t - 0.09
vy = -3.826t +1.412
(a)
Initial Speed
vx = dx/dt = 0.66 m/s
vy = -3.826*0 +1.412 = 1.412 m/s
v = (vx^2 + vy^2)^(1/2)
v = (0.66^2 + 1.412^2)^(1/2)
v = 1.56 m/s
(b)
angle = arctan(vy/vx)
angle = arctan(1.412/0.66)
angle = 64.95
(c)
ay = d(vy)/dt
ay = -3.826 m/s^2
ax = d(vx)/dt
ax = d(0.66)/dt = 0 m/s^2