Assi it?dep 16926853 Substitute n into from the above equation: (a + g-ma : subs
ID: 1789327 • Letter: A
Question
Assi it?dep 16926853 Substitute n into from the above equation: (a + g-ma : substitute Equation (4) and the value of T from Equation (3) into Equation (1): F cos -A(mg-f sin er Solve for a in terms of u, mi, m2, 9, F, and ((F.cose-ak.(m2-g-F-sin )_m1g) ml +m2 e: (5) Your answer cannot be understood or grac a= Finalize The acceleration of the block can be either to the right or to the left depending on the sign of the numerator in Equation (5). If the motion is to the left, we must reverse the sign of f, in Equation (1) because the force of kinetic friction must oppose the motion of the block relative to the surface. In this case, the value of a is the same as in Equation (5), with the two plus signs in the numerator changed to minus signs MASTER IT Consider the system described in the example with m 0.51 kg and m 0.40 kg. The coefficient of static friction between the block and the surface is 0.45, The angle of the force Fis equal to 22.0, in Fs 0, you can easily show that the block will accelerate to the left since the maximum static friction force is not sufficient to keep the block at rest. If F is sufficiently large, it is clear that the block will accelerate to the right. Find the range of F that allows the system to remain at rest. F. = 3.07 F746Explanation / Answer
F min acts when friction and F will help to keep the system at rest
hence
0.51g =Fcos22+0.45(0.4g-Fsin22)
hence Fmin =4.26 N
......................
for F max is when friction opposes F
ie
0.51g =Fcos22 -0.45(0.4g-Fsin22)
hence Fmax =6.17N