Part A Two slits spaced 0.0720 mm apart are 0.800 m from a screen. Coherent ligh

Question

Part A Two slits spaced 0.0720 mm apart are 0.800 m from a screen. Coherent light of wavelength passes through the two slits. In their interference pattern on the screen, the distance from the center of the central maximum to the first minimum is 3.00 mm The intensity at the peak of the central maximum is 0.1000 W/m2 What is the intensity at point on the screen that is 2.00 mm from the center of the central maximum? Express your answer with the appropriate units I-Value Units Submit My Answers Give Up Incorrect; Try Again; 4 attempts remaining Part B What is the intensity at point on the screen that is 1.50 mm from the center of the central maximum? Express your answer with the appropriate units |= | Value Units Submit My Answers Give Up

Explanation / Answer

the condition for dark fringe is d*sin(theta) = (m+0.5)*lamda

for first dark fringe m = 0 then

d*sin(theta) = (0+0.5)*lamda

0.072*106-3*sin(theta) = 0.5*lamda

disatnce from central maximum to first minimum is y = m*lamda*L/(2*d)

3*10^-3 = 1*lamda*0.8/(0.072*10^-3)

lamda = 270 nm

Intensity is I = Io*cos^2(pi*d*y/(lamda*L))

Given that Io = 0.1 W/m^2

then

I = 0.1*cos^2(3.142*0.072*10^-3*2*10^-3/(270*10^-9*0.8))

I = 0.09986 W/m^2

Part B)

I = Io*cos^2(pi*d*y/(lamda*L))

I = 0.1*cos^2(3.142*0.072*10^-3*1.5*10^-3/(270*10^-9*0.8))

I = 0.09992 W/m^2

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