Question
chapter 13 problem 5
ignment MESSAGE MY INSTRUCTOR FULL SCREEN PRINTER VERSION BAcK NEXT Focus on Concepts, Question 5 Heat is conducted through the two stlabs shown in the drawing. The dlabs have identical thicknesses and cross sectional areas, but they are made from different materials. The thermal conductivity of slab 1 is k1 110 J/(s-m-Co). What is the thermal conductivity k2 of slab 2? 65 °C 45 C 35 °C k2 Number 1 Units Use correct number of significant digits; the tolerance is +/-2% By accessing this Question Assistance, you will learn while you earn points based on the Point Potential Policy set by your Question Attempts: 0 of 5 used SAVE FOR LATER en/shared/ass aglist. uni?ide asnmt 1963634#N 1 0082 -08 PM eRO17 earch
Explanation / Answer
Solution:
As the slabs are having equal area and thickness So Using ,
k1 x Delta T1 = k2 x Delta T2
=> 110 x 20 = k2 x 10
=> k2 = 220 J/(s·m·C°).
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