Could you help with parts c and d A NASA space probe is traveling from the Earth

Question

Could you help with parts c and d

A NASA space probe is traveling from the Earth (average orbital radius, rE = 149.6 x 106 km; period of revolution, TE = 1.00 yrs) to Mars (average orbital radius, rM = 227.9 x 106 km; period of revolution, TM = 1.881 yrs). Treat the orbit of Mars and Earth as circles, with the Sun at the center. The trip takes tEM = 11 months. The average length of a month is 30.436875 days. 25% Part (a) Calculate the orbital velocity, vE, of Earth in m/s. 25% Part (b) Calculate the orbital velocity, vM, of Mars in m/s. Correct Answer Student Answer Final Grade vM = 24120 vM = 24120 100% Grade Detail Correct Student Feedback Final Answer Credit 100% Submission History Answer Hints Feedback Totals 1 vM = 24120 0% 0% 0% 0% Totals 0% 0% 0% 0%

25% Part (c) Assume that the probe starts at rest on the surface of the Earth and comes to rest on the surface of Mars. Calculate the average tangential acceleration, apt in m/s2, of the probe over its journey.
25% Part (d) Calculate the change in the radial acceleration, apr in m/s2, of the probe relative to the Sun, as it travels from Earth to Mars.

Could you help with parts c and d

Explanation / Answer

Part C:

Tangential acceleration apt is obtained as

X = ut + 0.5 at^2

Acceleration apt = 2X/t^2

apt= (Xm-Xe)/t^2

t = 11 months

t = 11 * 30.436875 * 24* 60*60

t = 28927206 sec

Xm-Xe = 227.9 – 149.6 = 78.3 *10^6 Km

So apt = (2*78.3*10^6)^2/(289270206)

apt= 4.2388 *10^-4 m/s^2

part D:

radial acceleration apm   = Vm^2/R

apm = (24.12*1000)^2/(227.9*10^9)

apm = 2.55*10^-3 m/s^2

ape = Ve^2/r

Ve = 2pir/T

Ve = (2*3.14* 149.6 *10^9)/(1*12*30.436875*24*60*60)

Ve = 2.9771*10^4 m/s

Ape = (2.9771*10^4)^2/(149.6*10^9)

Ape = 5.92 *10^-3 m/s^2

So change in acceleration = (2.55*10^-3- 5.92*10^-3) =

Aradial = -3.37*10^-3 m/s^2

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