In the sketch F1 and F3 are directly to the right and left of the center of the
ID: 1794186 • Letter: I
Question
In the sketch F1 and F3 are directly to the right and left of the center of the disk respectively and F2 and F4 are above and below the center respectively. All forces are applied at the edge except F2 which is applied halfway between the center and edge of the object. If the radius of the object is 2 meters, F1 is 30 Newtons, F2 is 25 Newtons Fa is 50 Newtons, and F4 is 42 Newtons. If the moment of inertia of the disk is 11 kg m2 about its center, what is the angular acceleration, in rad/s2, of the object about its center produced by these forces only? If it is clockwise include a negative sign F4Explanation / Answer
here,
F1 = 30 N
F2 = 25 N
F3 = 50 N
F4 = 42 N
moment of inertia , I = 11 kg.m^2
equating the torque
F3 * r + F4 * 0 - F1 * r - F2 * r/2 = I * alpha
50 * 2 - 30 * 2 - 25 * 2/2 = 11 * alpha
alpha = 0.45 rad/s^2
the angular accelration is 0.45 rad/s^2 counterclockwise