An oil tanker in the shape of a rectangular solid is filled with oil (Peil-880 k
ID: 1794330 • Letter: A
Question
An oil tanker in the shape of a rectangular solid is filled with oil (Peil-880 kg/m3). The flat bottom of the hull is 48.0 m wide and sits 26.0 m below the surface of the surrounding water. Inside the hull the oil is stored to a depth of 24.0 m. The length of the tanker, assumed filled with oil along the entire length, is 280 m. water water O1 26.0 m 24.0 m 26.0 m 24.0 m 280.0 m 48.0 m View from Rear View from Side Note: = 1.015 x 103 kg/m: rectangular solid -length x width x height. salt water solid At the bottom of the hull, what is the water pressure on the outside and the oil pressure on the inside of the horizontal bottom part of the hull? Assume the Po above the oil is the same as the Po above the water and its value is P 1.01 × 105 N/m2 If you did part A correctly you determined that the water pressure on the horizontal bottom part of the hull is larger than the oil pressure there. Explain why this MUST be the case. What buoyant force does the tanker feel? What is the weight of the tanker, excluding the weight of the oil in the hull? A. C.Explanation / Answer
Ans:-
A]Pw = P0 + gh
= 1.01*10^5 +1.015*10^3*9.8*26
= 3.6*10^5Pa
Poil = P0 + gh
= 1.01*10^5 +880*9.8*24
= 3.1*10^5Pa
B] Yes water Pressure is larger than the oil pressure
Pressure means force of that area and force means
F= m*g
So mass of water is greater than the mass of oil
That’s why pressure of the water is greater than the oil
C] Fb = mg = w *Vw *g
= 1.015*10^3 * 280*48*26*9.8
= 34.75*10^8N
D]Woil = mg = o*Vo *g
=880*280*48*24*9.8
= 27.82*10^8N
Wt= Wt-Wo = 34.75*10^8-27.82*10^8 =69.32*10^7N