I have the solution to the problem but what I can not understand is how they cam

Question

I have the solution to the problem but what I can not understand is how they came up with the equation for the node that has four either incoming or outgoing current. The equation being (12= ((V_{a}-V_{b})/4) +(V_{a}/28) + (V_{a}/14)) I understand where the first two terms were derived from, but I dont understand where they got the 14 ohm resistor for the third term. The same resistor being used in the second equation which is (((V_{a}-V_{b})/4) + (V_{a}/14) = V_{b}/8) Essentially I would like an explanation on how we get a 14 ohm resistor in context with the equations. Thanks in advance.Side Note: As far as choosing the course when asking a question my course Electrical Networks is not an option, so I chose Physics II. Is there anyway to get a class added to the list?

Explanation / Answer

from the figure

I=Va/28

so

2I =Va/14

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