In the system shown below, both rigid bars AB and DE have a length of 0.2 meter.
ID: 1821315 • Letter: I
Question
In the system shown below, both rigid bars AB and DE have a length of 0.2 meter. At the instant shown, bar AB has a constant angular velocity of 5 rad/s clockwise. Determine the angular accelerations of bars BD and DEExplanation / Answer
You are solving for alpha BD and alpha DE. First you need to find the angular velocities of each rod. Each rod will have a separate omega. AB has W1, BD has W2, and DE has W3. To do this you will use the equation of Vb= Vd + V d/b ----> (V d/b is in terms of W2) You relate Vd and Vb to its respective fixed point in terms of its own omega. You will end up with two equations ( i and j direction) and 2 unknowns ( W2 and W3). Once you solve for this omegas, you repeat the same process but for acceleration. The only difference is that in acceleration you will use; Ab= alphaBE X Rab + W1 X W1 X Rab To relate point B to its fixed point. You use the same equation to relate D to point E (replacing alphaDE and Red). And then you finally use Ab= Ad + A b/d to get two equations and two unknowns. Hope this helps!