The peak-hour volumes at two locations were counted and found to be equal. Howev
ID: 1827523 • Letter: T
Question
The peak-hour volumes at two locations were counted and found to be equal. However, the PHFs were .85 at the first location and .60 at the second. Describe the difference between the two locations if t=5 min.Explanation / Answer
As we know that ==>PHF = (peak-hour volume)/(4*peak-fifteen minute volume) ==>As peak-hour volume for both the locations are EQUAL ==>Let peak-hour volume = p ==>Therefore ==>0.85 = p/(4*peak-fifteen minute volume at First Location) ==>0.60 = p/(4*peak-fifteen minute volume at Second Location) ==>Therefore ==>(peak-fifteen minute volume at First Location)/(peak-fifteen minute volume at First Location) = 60/85 = 0.70588