A very small object carrying-6.0 uC of charge is attracted to a large, well anch

Question

A very small object carrying-6.0 uC of charge is attracted to a large, well anchored positively charged object. How much kinetic energy does the negativity charged object gain if the potential difference through which it moves is 3.0mV? Please show steps A very small object carrying-6.0 uC of charge is attracted to a large, well anchored positively charged object. How much kinetic energy does the negativity charged object gain if the potential difference through which it moves is 3.0mV? Please show steps Please show steps

Explanation / Answer

Work done by the electric field :

W = V*q = 3*10^-3*6*10^-6 = 1.8*10^-8 J

Now, by conservation of energy, change in Kinetic energy = Work done

So, KE gained = 1.8*10^-8 <--------answer

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---