Maximum height ? Earlier time at half maximum height: Waiter time at half maximu
ID: 1838958 • Letter: M
Question
Maximum height ? Earlier time at half maximum height: Waiter time at half maximum height:
You throw a baseball directly upward at time t-0 at an initial speed of 13.9 m/s. What is the maximum height the ball reaches above where it leaves your hand? At what times does the ball pass through half the maximum height? Ignore air resistance and take g = 980 ms Maximum height Number Eartier time at half maximum height: Number The Later time at half maximum height: O He o wel o Tech careers partnersprivacy pol
Explanation / Answer
In vertical,
initial velocity, u = 13.9 m/s
acc; , a = - 9.80 m/s^2
at maximum height, velocity will be zero so v = 0
Applying, v^2 - u^2 = 2 a d
0^2 - 13.9^2 = 2(-9.8) (H)
H = 9.86 m .............Ans
for half the maximum height, displacement d = H/2 = 4.93 m
Applying, d = u t + a t^2 /2
4.93 = 13.9 t - 9.80 t^2 /2
4.9 t^2 - 13.9 t + 4.93 = 0
t = 0.416 sec OR 2.42 sec
Earlier time = 0.416 s
Later time = 2.42 s