I post another question that is the same as this and if you answer either one co
ID: 1846999 • Letter: I
Question
I post another question that is the same as this and if you answer either one correctly i will give you credit for both. Just post it for both and you can get 3000 points.
http://www.chegg.com/homework-help/questions-and-answers/please-make-sure-answer-neat-read--q5057046
James has built a capacitor of width W, length L, plate distanced, and has filled it with a dielectric material having a relative dielectric constant Gr. Assume L d & W d. The maximum voltage that James can apply to this Capacitor is limited by Vmax = Kd, where K is the breakdown strength of the dielectric Derive an expression for the maximum energy that can be stored in this Capacitor in terms of K & the volume of the dielectric If James wants to store the maximum energy per unit volume do the valves of L, W & d matter? If yes, explain how they matter. If no, then explain which parameters matter?Explanation / Answer
Area A = WL
C = ?0*?r*A/d = ?0*?r*WL/d
Vmax = kd
E = (1/2)*C*Vmax^2
= (1/2)*(?0*?r*WL/d)*(kd)^2 = (1/2)*(?0*?r*WL/d)*k^2d^2
E = (1/2)*(?0*?r*WL)k^2*d
E = (1/2)*(?0*?r*k^2)*(WLd)
volume of dielectirc V= WLd
(i) E=(1/2)*?0*?r*k^2*V
(ii) per unit volume
(E/V) = (1/2)*?0*?r*k^2
no it does not depends on L,W,d
It depends on ?r & k.