Can s omeone solve these questions with clear solutions please? If Li has units
ID: 1847302 • Letter: C
Question
Can someone solve these questions with clear solutions please?
If Li has units of Weber (Volts.seconds) and V/R has units of current (Ampere), then what are the units of L/R? (show your work) Given the circuit below, with R|=45.6 k ohm, R2=45.6 k ohm, C| = 10 nF and C2 = 10 nF. Find the time constant x of the circuit and the equation for the voltage across the capacitors as a function of time if the step voltage input is 2 V for t 0 For the RC circuit in the above, Calculate the time required for the voltage across the capacitors to rise to 3.5 Volts. Calculate the time required for the voltage across the capacitors to rise from 2.3 to 4.7 Volts (i.e., rise time) Given the following time-varying voltage across a 75/^F capacitor Find an expression for the current flowing into the capacitor Find the energy stored in the capacitor at time t = 5 seconds. Given the circuit below, with L = 200 mH and R = 1 k ohm, if the step voltage input is 0 V for t 0 Find an exponential expression for the current i(t) flowing through the inductor and resistor. Determine the energy stored in the inductor as the time becomes very long (approaching infinity).Explanation / Answer
6) Li = Volts.second
i=V/R= ampere
L/R = volts.second/(volts/ampere)
=apmere.second
7)Ceq = C1+C2 = 10 + 10 =20nF
Req = R1 II R2 = 45.6/2 =22.8 kohm
time constant = Req*Ceq = 45.6*10*10^-6 = 4.56*10^-4 second
for t<=0
Vstep=2V
Voltage acorss acapcitor = 2*e^-t/time constant + 5*(1-e^-t/time constant ) = 5 - 3*e^(-t/0.456m) V
8)(a)3.5V =5-3*e^(-t/0.456m)
t=0.3154 *10^-3 = 0.3154 ms
(b)2.3 =5-3*e^(-t1/0.456m)
t1= .048 ms
4.7=5-3*e^(-t2/0.456m)
t2=0.5 ms
rise time = t2 - t1 =0.453 ms
9) (a)
V(t) = 30e^(-t/10)
Q=CV
I=dQ/dt= C*dV/dt
I = 75*10^-6*(30*(-1/10))*e^(-t/10)
=-225 e^(-t/10) uA
(b) t=5second
V(5) = 30*e^(-5/10) =18.2V
Energy = (1/2)*C*V^2 = 12.416mJ
10) (a)
I=(V/R)*(1-e^(-tR/L))
= 5*(1-e^(-5000t)) mA
(b)
at very long time I=5 mA
Energy = (1/2)*L*I^2 =2.5 uJ