Consider the following system in a vertical plane. The slider moves from A to B

Question

Consider the following system in a vertical plane. The slider moves from A to B on a frictionless rod under the action of the constant external force F (as shown) ['constant' means neither magnitude nor direction of F changes]. The slider is initially at rest at point A. The spring is attached to the slider on one end and the fixed point O on the other end. Stiffness of the spring is k = 250 N/m. The unstretched length of the spring is 0.6 meters. Mass of slider, m = 2 kg Compute the speed of the slider at B Compute the normal force on the slider at point A and point B

Explanation / Answer

initial energy of spring=0.5*kx=250*((0.8^2+0.4^2)^0.5-0.6)=10.835J final energy of spring= 45 work done by force=K.E. of body+change in energy of spring 50*1.4cos30=0.5mv^2+(45-10.385) v=5.1m/s

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