Blocks A and B, which weigh 200 lb and 120 lb, respectively, are connected by a

Question

Blocks A and B, which weigh 200 lb and 120 lb, respectively, are connected by a rope as shown in Fig. P15-23a. During motion of the bodies, Determine the acceleration of block A and the tension in the rope connecting the bodies. Determine the acceleration of block A if block B is replaced with a constant force of 120 lb as shown in Fig. P15-23b. 120 lb Fig. PI 5-23 1 Blocks A and B, which weigh 200 lb and 120 lb, respectively, are connected by a rope as shown in Fig. P15-23a. During motion of the bodies, Determine the acceleration of block A and the tension in the rope connecting the bodies. Determine the acceleration of block A if block B is replaced with a constant force of 120 lb as shown in Fig. P15-23b. 120 lb Fig. PI 5-23

Explanation / Answer

1 lb = 0.453592 kg hence 200lb = 90.72 kg 120lb = 54.43 kg (a) tension in string = Mb * g = 54.43*9.8 = 533.42 N net upward force on A is 2T = 2(533.42) = 1066.85 hence acceleration = F/Ma = 1066.85/90.72 = 11.76 m/s^2 (b) answer will be same since tension in rope is still the same

Related Questions

Navigate

• Browse (All)
• Browse B
• Subjects

---