PLEASE SHOW WORK The Voltage divider as shown in following figure is a circuit f

Question

PLEASE SHOW WORK

The Voltage divider as shown in following figure is a circuit for a lot of measurement system. The resistance R1, a purchase part which has the nominal resistance 4000 (Ohm) with 1% variation, that is, 4000 plusminus 40 (Ohm). R2 is a thermistor with coefficients a = 1.403 times 10-4,b = 2.373 times 10-4,c = 9.827 times 10-8. One set of measurement is V in = 4.400(V) and V 0 = 2.598(V). What are the possible maximum and minimum resistances R2 due to the variation R1? What are the possible maximum and minimum temperatures of the thermistor due to the variation R1?

Explanation / Answer

For the values Vin = 4400 and Vo =2598......you got Vo=[ R2/(R1+R2) ]*Vin ...this gives R2 = 1.44R1 ......putting the maximum and minimum values of R1 as 4040 and 3960......you the max and min values or R2 as ......5817.6 and 5702.4.........

Now , 1/T = a+b*ln(R2) +c*ln(R2)^3.........

and on substituting the max and min values of R2 ....the respective temperatures can be obtained

.these are......443.2 and 442.2 K...........

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