Repeat Prob. 6/64, only now the 27-kg concrete block begins to move down the 20
ID: 1860130 • Letter: R
Question
Repeat Prob. 6/64, only now the 27-kg concrete block begins to move down the 20 incline as shown. All other conditions remain as in Prob. 6/64.
6/64: The coefficient of static friction for both wedge sur- faces is 0.40 and that between the 27-kg concrete block and the 20 incline is 0.70. Determine the minimum value of the force P required to begin moving the block up the incline. Neglect the weight of the wedge.
Explanation / Answer
the force acting on the block is
F = u_s x m x g x sinA
where u_s = 0.70,m = 27 kg,g = 9.8 m/s^2 and A = 20o
the work done is
W = F x S
where S is length of incline
we know that
W = K = (1/2)mv^2
where v is speed of block before coming to rest
or (1/2)mv^2 = F x S
or v = (2F x S/m)^1/2