a passenger automobile is advertised as having a fuel economy rating of 29 mi/ga
ID: 1860734 • Letter: A
Question
a passenger automobile is advertised as having a fuel economy rating of 29 mi/gal for highway driving .express the rating in the units of km/lclass="chg-suggest-term">
class="txt-hdr-sec">Explanation / Answer
1 gallon = 3.785 L ; 1 mi = 1.609 km
therefore 1 mi/ga = (1.609/3.785) km/L = 0.425
29 mi/ga = 29*0.425 km/L =12.32 km/L = fuel economy rate in km/L