Please show work to get credit, thanks for the help! A person is holding a weigh
ID: 1861779 • Letter: P
Question
Please show work to get credit, thanks for the help!
A person is holding a weight in the hand as shown in the figure. Calculate 1) the muscle force, and 2) the joint reaction force at the elbow and its orientation Angles: Angle of forearm-hand segment relative to horizontal (theta) = 30 degree Angle-of-insertion of M to forearm (alpha) = 60 degree Angle of J to X axis (mu) = unknown Forces: Forearm-hand segment weight (S) = 17 N Exercise weight (W) = 60 N Muscle force (M) = unknown Joint reaction force (J) at the elbow = unknown Moment arms: External moment arm to SY (EMASY) = 0.15 m External moment arm to WY (EMAWY) 0.35 m Internal moment arm to MY (IMA) 0.05 m Assume the forearm is held 30 degree s above rather than below the horizontal plane. Does the change in forearm angle alter the magnitude of the external torque? (Calculation is not required)Explanation / Answer
No, because the forces responsible for external tornal torque is Sy, Wy & My, they will not change if forearm is held 30 degree above , only the direction of x component of M, S & W will change ..hence the external torque will be unaffected