I have tank A with liquid A, with a pressure of 210kPa at position 0, the tube g

Question

I have tank A with liquid A, with a pressure of 210kPa at position 0, the tube goes up out of the top of tank A and then down to a height of 2.8 meters from the center of tank A to where it contacts mercury. From here the mercury goes down and then back up. From the center of tank A to top of the mercury is 2.2 meters. From here the tube continues up and then down into the top of tank B. From the center of tank A to the center of tank B is -3 meters as tank B is lower than tank A. From the top of the mercury to the center of tank B is 5.2 meters. So the tubing looks like this, there is a tank, an upside down U, a U and then another upside down U into tank B. Am I correct in density of liquid A * 2.8 then subtracting the density of the Mercury * (2.8 - 2.2), then subtracting the density of liquid B * (3.0 + 2.2)? Then I can multiply this total value by gravity and set equal to Pa - Pb, subtract Pa from my known value to find the pressure in tank B. Help is greatly appreciated.

Explanation / Answer

yes your procedure is correct for calculation of pressure

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---