For the following two questions, consider circuits built from capacitors C1 = 11

Question

For the following two questions, consider circuits built from capacitors C1 = 11.3µF, C2 = 24.2µF, and C3 = 48.9µF, and a battery with Vbatt = 6.2V.   These are close to the actual capacitance values you will use in the lab, which are about 10% higher than the nominal values printed on the capacitors themselves.    Do all of your work (including circuit diagrams) in the spaces provided below.   Record your answers in the blanks, and also on the right side of Tables 1 and 2 of the lab report; they will serve as rough predictions for the measurements you will make during the lab experiment.

please show work and answer

Calculate the equivalent parallel capacitance: Ce%- AF a. b. Determine the voltages Vi, V2, and Vs across the three capacitors: Vi V, v, V. c. Determine the charges Qi, Q2, and Qs on the three capacitors: Qi

Explanation / Answer

If all the capacitors are connected in parallel then equivalent capacitance is given by

C= c1+c2+c3

= 11.3+24.2+48.9

= 84.4 uF

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As all the capacitance are in parallel so all share equal value of voltage i.e voltage applied

V1 = V2= V3= 6.2 V

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Charge on any capacitor is given by

Q= CV

So charge on capacitor 1

Q1= C1*V1= 11.3*6.2= 70.06 uC

Charge on capacitor 2

Q2= 24.2* 6.2= 150.04 uC

Charge on capacitor 3

Q3= 48.9*6.2= 303.18 uC

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Comment in case any doubt..goodluck

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