Problem 6.63 Part A Constant The two identical pucks in (Figure 1) rotate togoth

Question

Problem 6.63 Part A Constant The two identical pucks in (Figure 1) rotate togother on a frictionless, horizontal table. They are tied together by strings and 2, each of length L. If they rotate together at a frequency f. what is the tension in the string 1? Express your answer in terms of the variables m, f-l, and constant ?. Submit X Incorrect; Try Again; 2 attempts remaining The correct answer involves the variable f. which was not part of your answer Figure 1 Part B If they rotate together at a frequency f, what is the tension in the string 2? Express your answer in terms of the variables m, f. I, and constant w. 17 2/ ?. Submit

Explanation / Answer

The force needed to cause circular motion is F = m w^2 r

For puck 1, r = L. For puck 2, r = 2L

(B) The only force on puck 2 is the tension in string 2 (call it T2).

T2 = 2 m w^2 L

(A) The forces on puck 1 are T2 and the tension in string 1 (call it T1), in opposite directions.

T1 - T2 = m w^2 L

T1 = 3 m w^2 L

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