Part A For a gene suspected of causing hypertension in humans, you observe the f

Question

Part A For a gene suspected of causing hypertension in humans, you observe the following genotype frequencies: A1A1 0.574; AA2 0.339, A2A2 0.087. Is this gene in Hardy-Weinberg equilibrium? Why or why not? (Assume that a difference of three percent or more in any of the observed versus expected frequencies is statistically significant.) See Section 23.1 Page 458) View Available Hint(s) No. The expected genotype frequencies are A A1 0.553; A1A20.381; A2A2 0.166. No. The expected genotype frequencies are A1 A1 0 553 A1A2 0.381; A2A2 0.066. O Yes. The expected genotype frequencies are AjA1 0.574; AA2 0.339, A2A2 0.087 O Yes. The expected genotype frequencies are AA10.553, A1A2 0.381; A242 0.066. Submit

Explanation / Answer

Choice 3 is correct.

Reason: According to the Hardy-Weinberg equilibrium, the sum total of all the frequencies of all the gene alleles in a population must count to unity. Here, it can be clearly seen that the sum total of the allelic frequencies of this population counts to unity, hence this population is in Hardy-Weinberg equilibrium.

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