In a slap shot a hockey player accelerates the puck from a velocity of 8.00 m/s

Question

In a slap shot a hockey player accelerates the puck from a velocity of 8.00 m/s to 30.0 m/s in the same direction. If this takes 3.33 ? 10?2 s, calculate the distance over which the acceleration acts. _____m
ROUND ALL CALCULATIONS TO THE FOURTH DECIMAL PLACE!!!!! In a slap shot a hockey player accelerates the puck from a velocity of 8.00 m/s to 30.0 m/s in the same direction. If this takes 3.33 ? 10?2 s, calculate the distance over which the acceleration acts. _____m
ROUND ALL CALCULATIONS TO THE FOURTH DECIMAL PLACE!!!!!
ROUND ALL CALCULATIONS TO THE FOURTH DECIMAL PLACE!!!!!

Explanation / Answer

acceleration = change in velocity/time

= (30-8)/3.33*10-2

= 6.607*102 m/s2

now

v2 = u2 + 2*a*s

so s = v2 -u2 / 2*a

= 302 -82/ 2*660.7

= 0.6327 m

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