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ID: 1866007 • Letter: M
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McNeese State Universit ×?e Home I chegg.com xG how to screenshot on as × ? | www.saplinglearning.com/ibiscms/mod/ibis/view.php?id:5908382 a O Sapling Learning Jump to... Marwan Taha macmilan learning Attempts Score7/23/2018 10:00 PM 70/1007/17/2018 05:01 PM Print Caloulator -Parade Table Porodic Tablo Queston 2 ef 10 Available From: Due Date: Points Possible: Grade Category: 7/11/2018 06:00 AM 7/23/2018 10:00 PM 100 Greded Sapling Learning A pair of oonstant forces of magnitude F= 12.7 N is pplied to the figure. The diameter ofthe ale is d-8.67 mm. The angle ?, which has a value of 32.9". describes the steopness of the top's sloping sides. The moment of inertia of the top about its spin axis is -0.747 kg m What is the tangential acceleration a of the point labeled P, which is at a height of h 6.27 on above the foor? ite sides of the axle of a top, as shown in Policies: Rubric 1 Number You can check your answers You can view solutions after the due date You can keep trying to answer cach question until you get it right or give up. There is no penalty for incorrect answers. For multiple-choice questions, the penalty depends on the number of choices available. 10 1 O eTextbook O Help With This Topic frictionless floor Thore is a hint available! OWeb Help & Videos Vinw the botom dvider bar en the divider bar again to hide the hint Cose O Technical Support and Bug Reports 82011-2018 Sapling Learning, Inc. abour carearaprivay policy tarma ofuse contact ua halp 1:24 PM O Type here to search ^0-41)?7/19/2018 ?2Explanation / Answer
let r = d/2 = 0.004335 m
then torque T = F * r = 2 * 12.7N * 0.004335m = 0.110109 N·m
but also T = I*alpha, so 0.110109 N·m = 0.747kg·m² * alpha
alpha = 0.1474 rad/s²
applies to all points on the top.
tan(th) = R / h
tan32.9º = R / 0.0627m
R = 0.04056 m
so at point P, tangential a = alpha*R = 0.1474rad/s² * 0.04056m = 0.00598 m/s² = 0.598 cm/s²