I. A solenoid has a radius of 1.27 cm, a length of 80 cm, 360 turns, 450 turns/m

Question

I. A solenoid has a radius of 1.27 cm, a length of 80 cm, 360 turns, 450 turns/m, and a current of 5.5 A at its front and at its back as shown. Find the magnetic field at the center of the solenoid. (To show what's happening. the sketch is not to scale and shows many fewer coils at a much larger separation.) EQUATION USED SOLUTION ANSWER 5.5 A 5.5 A out in MAGNITUDE DIRECTION An 44 turn flat coil is in the plane of the paper. It has a radius of m. Its 5.5 A current is counterclockwise. Find the magnetic field of the circular coil at either of the two points on its axis that are 0.60 m from its center. ANSWER EQUATIO USED SOLUTION MAGNITUDE DIRECTION A toroid (sometimes called a toroidal solenoid) has T234 turns. It's wound of wire that has a 1.1 mm radius. Each (almost) circular turn of the toroid has a 1.0 cm radius. Within the turns (that is, in the "dough"), a distance of 44 cm from the toroid's center, you want a magnetic field of magnitude 3.1 mT. What must the current be? EQUATION USED SOLUTION ANSWER

Explanation / Answer

1. magnetic field due to a solenoid,

B = u0 n I  

putting values,

B = (4pi x 10^-7) (450) (5.5)

B = 3.11 x 10^-3 T Or 3.11 mT

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---