MasteringPhysics: HW 5 Ch 25-Google Chrome Secure https/session.masteringphysics

Question

MasteringPhysics: HW 5 Ch 25-Google Chrome Secure https/session.masteringphysics.com/myct/itemView?offset-nextBassignmentProblemID-89546550 HW 5 Ch 25 Problem 25.72 Constants Part A Consider the circuit shown in (Figure 1), The battery has emf 92.0 V and negligible internal resistance. Re 2 00 .C1:400 . and G-600 After the What is the final charge on C? Express your answer with the appropriate units. capaciors have atained their final chargos, the charge Value Units Submit Part B What is the resistance R? Express your answer with the appropriate units. : | Value Units Figure Submit 1 of1 Return to Assignment Provide Feedback Ri R2 C2

Explanation / Answer

Solution-

A)

V=Q1/C1 =18u/4u =4.5 V

charge Q2 =C2*V =6u*4.5

Q2=27 uC

b)

Now from voltage division

V(R2)=e*(R2/R1+R2)

here V(R2)=V =4.5V

4.5 =92*(2/R1+2)

0.0489(R1+2)=1

0.0489R1=1-0.0978=0.9022

R1=18.45 ohms

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