An observer in reference frame S notes that two events are separated in space by
ID: 1873221 • Letter: A
Question
An observer in reference frame S notes that two events are separated in space by 200 m and in time by 0.81 s .
How fast must reference frame S be moving relative to S in order for an observer in S to detect the two events as occurring at the same location in space?
Express your answer using two significant figures.
An observer in reference frame S notes that two events are separated in space by 200 m and in time by 0.81 s .
How fast must reference frame S be moving relative to S in order for an observer in S to detect the two events as occurring at the same location in space?
Express your answer using two significant figures.
Explanation / Answer
if an observer in another frame has to observe the same event, the velocity of S' should be = 200m / 0.81 x 10^-6 = 246.91 x 10^ 6 m/s