Matter &Ihteractions;, 4e, Custom WileyPLUS Course for Contact California State
ID: 1873899 • Letter: M
Question
Matter &Ihteractions;, 4e, Custom WileyPLUS Course for Contact California State University Us I Log Out MECHANICS AND HEAT (Physic 151/152) Long Beach Assignment Gradebook ent FULL SCREEN A thin circular sheet of glass of diameter 6 meters is rubbed with a cloth on one surface, and becomes charged uniformly. A chloride lon (a chlonine atom which has gained one extra electron) passes near the glass sheet. When the chloride ion is near the center of the sheet, at a location 0.6mm from the sheet, It experiences an electric force of 6E-15 N, toward the glass sheet. In this problem, use the value = 8.85e-12 C2/(N-m2) It will be useful to you to draw a diagram on paper, showing field vectors, force vectors, and charges, before answering the folliowing questions about this situation. a) Which of the following statements about this situation are correct? Select all that apply The electric field of the glass sheet is equal to the electric field of the chioride ion The force on the chloride ion is equal to the electric field of the glass sheet. The net electric field at the location of the chloride ion is zero. The charged disk is the source of the electric field that causes the force on the chloride ion. The electric field that acts on the chloride ion is due to the charge on the glass shet and to the charge an the chlonde lon of a disk, the textbook derives two approximate formulas. In the current situation we want an answer that is correct 6)In addition to an exact formula for the electric field to 3 significant figures. Which of the following is correct? We should never use an approximation if we have enough information to do an exact calculation. z is nearly equal to R, so we have to use the exact formula. R, so we can't use an approximation. R z, so it is adequate to use the most approximate formula here. e) How much charge is on the surface of the glass disk? (give amount, including sign, and correct units 12.5 All Rights Reserved. A Division of Jghn Policy I s 2000-2018 John Wiley &Sons.; Ins AExplanation / Answer
1st question
The relevant equations here are E = (Q/A) / (20) and F = qE.
Substituting the first equation into the second, you get:
F = q * [(Q/A) / (20)] and, after solving for Q:
Q = (F * A * 20) / q
You’re given the value for 0 (8.85e-12 C^2/[N*m^2]) and F (6e-15N) and, using 6 meters as your diameter, you can find the area (A). Since the chloride ion has only one additional electron, you can use -1.6e-19C as your charge (q), which is the charge of a single electron.
The chloride ion has a negative charge and the electric force will be towards the disk, making the final answer positive, not negative.
We get:
Q = 1.8767E-5 C