Can someone please walk me through the steps to solving this problem? - points S

Question

Can someone please walk me through the steps to solving this problem? - points SercP11 18 Peo Consider the circuit shown in the figure below. (Assume R1-12.0 , R2 = 1.85 , and V = 6.75 V.) My Notes Ask Your 400 1 5000 mm'm 3.00 (a) Calculate the equivalent resistance of the R1 and 5.00-92 resistors connected in parallel. (b) Using the result of part (a), calculate the combined resistance of the R1, 5.00-2 and 4.00-2 resistors. (c) Calculate the equivalent resistance of the combined resistance found in part (b) and the parallel 3.00-92 resistor. (d) Combine the equivalent resistance found in part (c) with the R2 resistor. (e) Calculate the total current in the circuit. (f) What is the voltage drop across the R2 resistor? (9) Subtracting the result of part (f) from the battery voltage, find the voltage across the 3.00-2 resistor. (h) Calculate the current in the 3.00-2 resistor. Need Help? Read h

Explanation / Answer

1) if two resistors are in parallel then R to = R1R2/R1+R2

a) R1,5 = 12*5/12+5 = 3.53 ohm

b) R1,5 is in series with the 4 ohm

equivalent is = 3.53+4 = 7.53 ohm

c) equivalent in part b is in parallel with 3 ohm resistor

so equivalent = 7.53*3/7.53+3 = 2.14 ohm

d) Rtot = 2.14+1.85 = 3.99 ohm

e) from ohms law

v = iR

i = 6.75/3.99 = 1.69 amp

f) in series current is same across all the resistors

current on R2 is = 1.69 amp

f) v tot = 6.75 V

acroos R2 is v2 = 1.69*1.85 = 3.13 V

voltage across the 3 ohm is 6.75-3.13 = 3.62 V

in paralel voltage is same acroos the resistors

g) i3 = 3.62/3 = 1.21 amp

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