Consider the system known as Atwood\'s Machine (two masses hanging over a pulley

Question

Consider the system known as Atwood's Machine (two masses hanging over a pulley). Assume the two masses and are not equal.

Suppose and are increased by the same multiplicative factor (in other words, each mass is multiplied by the same number). What happens to the acceleration of the system?

a. The acceleration decreases.

b. The acceleration is unchanged.

c. The acceleration may increase, stay the same, or decrease, depending on the size of the multiplicative factor.

d. The acceleration increases.

Again, suppose and are increased by the same multiplicative factor. What happens to the tension in the rope?

a. The tension increases.

b. The tension is unchanged.

c. The tension may increase, stay the same, or decrease, depending on the size of the multiplicative factor.

d. The tension decreases.

Suppose and are increased by the same additive factor (in other words, each mass has the same amount of extra mass added to it). What happens to the acceleration of the system?

a. The acceleration decreases.

b. The acceleration increases.

c. The acceleration may increase, stay the same, or decrease, depending on how much mass is added.

d. The acceleration is unchanged.

Explanation / Answer

given atwood machine

a. acceleration , a = (m2 - m1)g/(m1 + m2)

so when same factor is multiplied to both masses

then acceleration still remoains the same

option b.

b. T = m1(g + a)

so when m1 is increased, T increase by the same multplicative constant

hecne option a.

c. a' = (m2 + m - m1 - m)g/(m1 + m2 + m + m) = (m2 - m1)g/(m1 + m2 + 2m)

hecne accelration of the system decreases

option a.

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects