A metal bar is in the xy -plane with one end of the bar at the origin. A force F
ID: 1876228 • Letter: A
Question
A metal bar is in the xy-plane with one end of the bar at the origin. A force F =( 7.79 N )i^+(-2.78 N )j^ is applied to the bar at the point x=2.16 m , y= 3.53 m .
1
What is the position vector r for the point where the force is applied?
Enter the x and y components of the radius vector separated by a comma.
2
What are the magnitude of the torque with respect to the origin produced by F ?
Express your answer with the appropriate units.
3
What are direction of the torque with respect to the origin produced by ?
+x-direction
+y-direction
+z-direction
x-direction
y-direction
z-direction
Explanation / Answer
A) vector r = 2.16m i + 3.53m j
B) = r x F = (2.16m i + 3.53m j) x (7.79N i - 2.78N j)
= -33.5N·m k
has magnitude 33.5 N·m.
C) -z direction
Hope this helps :)