A black mamba snake has a length of 2.97 m and a top speed of 3.40 m/s. Suppose

Question

A black mamba snake has a length of 2.97 m and a top speed of 3.40 m/s. Suppose a mongoose and a black mamba find themselves nose to nose. In an effort to escape, the snake accelerates at 2.92 m/s2 from rest. How much time does it take the snake to reach its top speed? time: How far does the snake travel in that time? distance: Assuming the mongoose remains stationary, once the snake reaches its top speed, has its tail gone past the mongoose? The tail of the snake has gone past the mongoose. The tail of the snake has not gone past the mongoose.

Explanation / Answer

Given,

L = 2.97 m ; v = 3.4 m/s ; a = 2.92 m/s^2

We know that

v = u + at

3.4 = 0 + 2.92 t => t = 1.16 s

Hence, t = 1.16 s

b)s = ut + 1/2 at^2

s = 0 + 0.5 x 2.92 x 1.16^2 = 1.98 m

Hence, d = 1.98 m

c)The tail of the snake has not gone past the mangoose.

since, 1.98 < 2.97 (length of snake)

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