Constants I Periodic Table Part A Four people participate in a rope compettion.

Question

Constants I Periodic Table Part A Four people participate in a rope compettion. Two of them pull the rope right exerting forces of magnitude 330 N and 380 N. The other two pull left exerting forces of magntude 320 Nand 410N. What is the sum of the forces exerted on the rope? Express your answer with the appropriate units. Enter positive value if the direction of the force is to the right and negative value if the direction of the force is to the left. Submit xIncorrect; Try Again; 9 attempts remaining

Explanation / Answer

Given that,

The forces exerted by the right side people are 330N and 380N

And the forces exerted by the left side people are 320N and 410N

So, the total force exerted towards right side = 330 + 380 = 710N

and the total force exerted towards left side = 320 + 410 = 730N

Therefore, the sum of the forces exerted on the rope = sum of the forces exerted by right side people - sum of the forces exerted by left side people

=> sum of the forces exerted on the rope = 710N - 730N = ( -20N )

( Here, the negative sign indicates that the direction of the force is to the left side )

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