Please answer both questions. I appreciate you!! A 67.0-m length of coaxial cabl

Question

Please answer both questions. I appreciate you!!

A 67.0-m length of coaxial cable has an inner conductor that has a diameter of 2.58 mm and carries a charge of 8.10 C. The surrounding conductor has an inner diameter of 7.27 mm and a charge of -8.10 HC. Assume the region between the conductors is air. (a) What is the capacitance of this cable? (b) What is the potential difference between the two conductors? kv Two small beads having positive charges q1 = 4q and q2 = q are fixed at the opposite ends of a horizontal i sulat ng rod of shown in the figure below, a third small, charged bead is free to slide on the rod nat d 1 m. The bead th har e sat the ong . A 91 92 (a) At what position x is the third bead in equilibrium?

Explanation / Answer

1)

a)

capacitance per unit length of cable is

C = L/2Ke*(1/ln(b/a))

C = [67 / (2 x 9 x 10^9)]*(1 / ln(7.27/2.58)

C = 3.7222 x 10^-9 x 0.965

C = 3.592 x 10^-9 F

C = 3.592 nF

b)

potential difference is

V = Q/C

V = (8.1 x 10^-6 C) / (3.592 x 10^-9 F)

V = 2254 V = 2.254 KV

2)

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