A positive charge of 4.60 C ís fixed in place. From a distance of 4.10 cm a part

Question

A positive charge of 4.60 C ís fixed in place. From a distance of 4.10 cm a particle of mass 5.20 g and charge +3.30 uC is fired with an initial speed of 74.0 m/s directly toward the fixed charge. How close to the fixed charge does the particle gef before it'comes to rest and starts traveling away? 7.77x101 The particle comes to rest when it has no kinetic energy. The change in kinetic energy will be equal to the increase in electrical potential energy. Note that the particle has some potential energy at the starting point. Subomit Ansewer Incorrect. Tries 3/20 Previous Tries

Explanation / Answer

Using conservation of energy

Loss in kinetic energy= invrease in potential energy

0.5mv^2= kq1*q2*(1/r1-1/r2)

0.5*5.2*10^-3*74^2= 9*10^9*4.6*10^-6*3.3*10^-6*(1/r-100/4.1)

r= 7.78*10^-3 m

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