Parts A through E. please help. thanks Constants Part A g agh tma function of ti
ID: 1882262 • Letter: P
Question
Parts A through E. please help. thanks
Constants Part A g agh tma function of time is plotted in tho tigure. (Figure 1) What is its instantareous velocity at T10.0s? Expross your answer to two significant figures and include the eppropriate units n(10) " I Value Units Part B What is its instantaneous velocity at t-300s? Express your answer to two signitficant figures and include the appropriate units. Figure 1 of 1 (30) Value Units 20 Submit x 10 Part C 10 20 30 40 50 What is its average velocty between0 andt5.0s? Express your answer to two significant figures end include the appropriste units t (slExplanation / Answer
Second time I am solving this same problem, please have a look into it
Solution,
A)
Make a tangent line at t = 10 s to find the instantaneous velocity by its slope. This is the less steep of the two blue lines above. This line seems to have a slope of rise/run = 14 m/50 s = 0.28 m/s
B)
Make a tangent line at t = 30 s, and find its slope (this is the velocity). This is the steeper of the two blue lines. This line rises 25 m between 17 and 37 seconds, so it has a slope of about 25 m/20 s, which is about 1.25 or 1.2 m/s.
C)
Average velocity is just total displacement divided by total time. From 0 to 5 seconds it seems to go from 0 to about 1.5 m (read from the graph), and the time is of course 5 seconds, so the average velocity is 1.5 m/5 = .3 m/s
D)
From 25 to 30 the rabbit displaces from 8 m to 16 m (read from the graph), again in 5 seconds giving an average velocity of 8m/5 s = 1.6 m/s
E)
From 40 to 50 seconds the rabbit displaces from 20 m to 10 m (read from the graph), now in 10 seconds giving an average velocity of -10m/10s = -1.0 m/s
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